Solveeit Logo

Question

Question: If \[f(x) = \ln ({x^2} + 7\left| x \right| + 10)\] is a single valued real function then the range o...

If f(x)=ln(x2+7x+10)f(x) = \ln ({x^2} + 7\left| x \right| + 10) is a single valued real function then the range off(x)f(x) in its natural domain will be
A) [0,+][0, + \infty ]
B) [ln10,+][\ln 10, + \infty ]
C) [0,10][0,10]
D) RR

Explanation

Solution

Here we will form a condition as the log function is present in the given equation. Then we will analyze and solve the equation. Simplifying the equation further we will get the natural domain of the given functionf(x)f(x).

Complete step by step solution:
The given function isf(x)=ln(x2+7x+10)f(x) = \ln ({x^2} + 7\left| x \right| + 10)
Firstly we will form a condition as the log function is present. So, from the given expression we can say that the log term is positive as log can only take the positive value. Therefore, we get
x2+7x+10>0{x^2} + 7\left| x \right| + 10 > 0………………. (1)\left( 1 \right)
This condition is valid for both the positive and negative value of the variable xx.
Now from the equation (1)\left( 1 \right) we can see that it have a term of
x2{x^2}. So, whatever the value ofxx is i.e. positive or negative. The value of this term i.e. x2{x^2} is always positive.
Similarly from the equation (1)\left( 1 \right) we can see that it have a term of7x7\left| x \right|. So, whatever the value of xx is i.e. positive or negative. The value of this term i.e. 7x7\left| x \right| is always positive because the variable xx is in the mod function.
So by this we came to know that the value of the expression x2+7x+10{x^2} + 7\left| x \right| + 10 is always positive.
So the upper limit of the function is positive infinity i.e. ++ \infty.
Now we have to find out the lower limit of the function. So, by putting the value ofx=0x = 0 in the equation (1)\left( 1 \right) we will get the lower limit of the function. Therefore, we get
x2+7x+10=02+7×0+10=10\Rightarrow {x^2} + 7\left| x \right| + 10 = {0^2} + 7 \times \left| 0 \right| + 10 = 10
So, x2+7x+1010 \Rightarrow {x^2} + 7\left| x \right| + 10 \ge 10
Applying natural log to both sides, we get
ln(x2+7x+10)ln(10)\Rightarrow \ln \left( {{x^2} + 7\left| x \right| + 10} \right) \ge \ln \left( {10} \right)
f(x)ln(10)\Rightarrow f(x) \ge \ln \left( {10} \right)
So,ln(10)\ln \left( {10} \right) is the lower limit of the function and ++ \infty is the upper limit of the function.
Hence, the natural domain of the functionf(x)f(x) is [ln10,+][\ln 10, + \infty ]

So, option B is the correct option.

Note:
We should know that the natural domain of a function is the range of the function where its value can lie. Also we should know that the value of any term inside the log function is always positive; it can never be negative. Also we have to keep in mind the type of bracket which should be used to show the natural domain of the function. Either the brackets may be open bracket or closed bracket.
Open bracket is used to show the natural domain of the function when the end points are not included in it. For example: (2,15)(2,15) which means 2<x<152 < x < 15.
Closed bracket is used to show the natural domain of the function when the end points are included in it. For example: [2,15][2,15] which means 2x152 \le x \le 15.