QuestionReportMathematics Question on Relations and functionsIf f(x)=ln(1−x21+x2)f(x) =ln(\frac {1-x^2}{1+x^2})f(x)=ln(1+x21−x2) then value of 225(f′(x)–f′′(x))225(f'(x) – f''(x))225(f′(x)–f′′(x)) at x=12x=\frac 12x=21AnswerThe answer is 736.
