Question

If f (x) = $\left( - \frac{1}{2},\frac{1}{9} \right)$ then –

• A. $\left\lbrack - \frac{1}{4},\frac{1}{4} \right\rbrack$f (x) = e^–6
• B. $f(x) = \frac{x + 2}{|x + 2|}$ f (x) = 2
• C. $R - \{ - 2\}$f (x) = e^–3
• D. $f(x) = \sec\left( \frac{\pi}{4}\cos^{2}x \right), - \infty < x < \infty$ f (x) = e^–4

Answer 1

Answer: (D)

$f(x) = \sec\left( \frac{\pi}{4}\cos^{2}x \right), - \infty < x < \infty$ f (x) = e^–4

Answer 2

$\lim _ { x \rightarrow \infty }$ $\left( \frac { x } { 2 + x } \right) ^ { 2 x }$ ; 1^∞ form ⇒ $\mathrm { l } _ { \mathrm { x } \rightarrow \infty } \left( \frac { - 2 } { 2 + \mathrm { x } } \right) ^ { 2 \mathrm { x } }$ = e^–4