Question
Question: If f (x) is a function such that f (0) = 2, f (1) = 3 and f (x + 2) = 2 f (x) – f (x + 1) for \[\for...
If f (x) is a function such that f (0) = 2, f (1) = 3 and f (x + 2) = 2 f (x) – f (x + 1) for ∀x∈R, then f (5) is:
(A). 5
(B). 13
(C). 3
(D). -5
Solution
Hint: First write all the known relations and values at once. Now substitute x = 0 in the relation. Use the above known values, given in the question to find the unknown. Now increase the value of x by 1 repeat the process. Repeat all the steps till you get the functional value which you require f (5). Stop at this point which is the required result.
Complete step-by-step solution -
The first functional value given in the question in the question is:
⇒f(0)=2 - (1)
The second functional value given in the question is:
⇒f(1)=3 - (2)
The relation between f and x given in the question is:
⇒f(x+2)=2f(x)−f(x+1) - (3)
By substituting x = 0 in above equation, we get it as:
⇒f(2)=2f(0)−f(1)
By substituting the functional values, we get it as follows:
⇒f(2)=2(2)−3
By simplifying the above equation, we get it as follows:
⇒f(2)=4−3=1
By substituting x = 1 in equation (3), we get it as follows:
⇒f(3)=2f(1)−f(2)
By substituting the function values in above equation, we get it as:
⇒f(3)=2(3)−1
By simplifying the above equation, we get it as:
⇒f(3)=6−1=5
By substituting x = 2 in equation (3), we get the equation as:
⇒f(4)=2f(3)−f(2)
By substituting the functional values in above equation, we get:
⇒f(4)=2(5)−1
By simplifying the above equation, we get it as follows:
⇒f(4)=10−1=9
By substituting x = 3 in equation (3), we get the equation as:
⇒f(5)=2f(4)−f(3)
By simplifying the functional values, we get it as follows:
⇒f(5)=2(9)−5
By simplifying the above equation, we get it as follows:
⇒f(5)=18−5=13
So, the value of f (5) is 13 such that it satisfies the given condition.
Therefore option (b) is the correct answer for the given question.
Note: Be careful while calculating functional value: every functional value is dependent on others indirectly. So, if you make mistakes in any functional value, the whole answer might be wrong. Generally, by seeing the f (0), f (1) values students have a misconception of f (x) = x + 2 and they solve it, but it is a very big mistake. Even if you assume like this you must first verify in the relation do not blindly solve by the assumption.