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Question: If f (x) = \(\int_{0}^{x}{(t + 1)}\) (e<sup>t</sup> –1) (t – 2) (t + 4) dt then f (x) would assume t...

If f (x) = 0x(t+1)\int_{0}^{x}{(t + 1)} (et –1) (t – 2) (t + 4) dt then f (x) would assume the local minima at

A

x = –4

B

x = 0

C

x = –1

D

None of these

Answer

x = –1

Explanation

Solution

Here, f(x)f'(x) = (x + 1) (ex – 1) (x – 2) (x + 4)

Clearly x = –1 and x = 2 are the points of local minima