Question
Question: If f (x) = \(\int_{0}^{x}{(t + 1)}\) (e<sup>t</sup> –1) (t – 2) (t + 4) dt then f (x) would assume t...
If f (x) = ∫0x(t+1) (et –1) (t – 2) (t + 4) dt then f (x) would assume the local minima at
A
x = –4
B
x = 0
C
x = –1
D
None of these
Answer
x = –1
Explanation
Solution
Here, f′(x) = (x + 1) (ex – 1) (x – 2) (x + 4)

Clearly x = –1 and x = 2 are the points of local minima