Question

If f(x) =$\begin{cases}\frac{x^2-9}{x-3}, x≠3 \\\ 5, x=3 \end {cases}$ then f(x):

• A. is continuous at x = 3
• B. has removable discontinuity at x =3
• C. has irremovable discontinuity at x=3
• D. continuous at every real number

Answer 1

Answer: (B)

has removable discontinuity at x =3

Answer 2

The correct option is (B):has removable discontinuity at x =3