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Question

Mathematics Question on Continuity and differentiability

If f(x)={1cos4xx2x0 kx=0f(x)=\begin{cases} \frac{1-\cos4x}{x^2} & x\ne0 \\\ k & x=0 \end{cases} is continuous at x = 0, then the value of k is :

A

8

B

7

C

6

D

4

Answer

8

Explanation

Solution

The correct option is (A) :8.