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Question: If \(f(x) = 3{x^2} + 15x + 5\), then the approximate value of \(f(3.02)\)is A.47.66 B.57.66 C....

If f(x)=3x2+15x+5f(x) = 3{x^2} + 15x + 5, then the approximate value of f(3.02)f(3.02)is
A.47.66
B.57.66
C.67.66
D.77.66

Explanation

Solution

Hint: Here the value of f(3.02)f(3.02) is calculated by substituting the value of xx as 3.02 in given f(x).

Complete step-by-step answer:

The Given function is f(x)=3x2+15x+5f(x) = 3{x^2} + 15x + 5
Now putting the value of xx as 3.02 we get
f(3.02)=3(3.02)2+15(3.02)+5 f(3.02)=3(9.1204)+45.3+5 f(3.02)=27.3612+45.3+5 f(3.02)=77.6612≃77.66  f(3.02) = 3{(3.02)^2} + 15(3.02) + 5 \\\ f(3.02) = 3(9.1204) + 45.3 + 5 \\\ f(3.02) = 27.3612 + 45.3 + 5 \\\ f(3.02) = 77.6612 \simeq 77.66 \\\
So the required solution is (d) 77.66.

Note: In these types of questions, we get a solution just by substituting the value of xx in the given function. One should take care of decimal points while keeping the calculation to appropriate value.