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Question

Mathematics Question on Functions

If f:R2Rf : R - \\{2\\} \to R is a function defined by f(x)=x24x2f(x) = \frac{x^2 - 4}{x - 2} , then its range is

A

R

B

R - {2}

C

R - {4}

D

R - {-2, 2}

Answer

R - {4}

Explanation

Solution

We have,
f(x)=x24x2,x2f(x)=\frac{x^{2}-4}{x-2}, x \neq 2
f(x)=(x+2)(x2)x2,x2f(x)=\frac{(x+2)(x-2)}{x-2}, x \neq 2
f(x)=(x+2),x2f(x)=(x+2), x \neq 2
\therefore Range of f(x)=R4f(x)=R-\\{4\\}