Question
Question: If \[f\left( x \right) = \log x\], \[g\left( x \right) = {x^3}\], then \[f\left[ {g\left( a \right)}...
If f(x)=logx, g(x)=x3, then f[g(a)]+f[g(b)] equals
(a) f[g(a)+g(b)]
(b) 3f(ab)
(c) g[f(ab)]
(d) g[f(a)+f(b)]
Solution
Here, we have to find the value of the composite function. Composite functions are those functions where one function is formed after putting another function inside it. To solve the question we will simplify the function in terms of a and b. Then, we will apply the rules of logarithms to simplify the expression further, and get the correct option as the answer.
Formula used: We will use the rules of logarithms logxn=nlogx and logx+logy=log(xy).
Complete step by step solution:
We will use the rules of logarithms to simplify the expression.
First, we will find the value of g(a) and g(b).
Substituting x=a in the function g(x)=x3, we get
⇒g(a)=a3
Substituting x=b in the function g(x)=x3, we get
⇒g(b)=b3
Next, we will find the value of f[g(a)].
Substituting x=g(a) in the function f(x)=logx, we get
⇒f[g(a)]=log[g(a)]
Substituting g(a)=a3in the expression, we get
⇒f[g(a)]=loga3
We know the rule of logarithms logxn=nlogx.
Substituting x=a and n=3 in the rule of logarithms logxn=nlogx, we get
⇒loga3=3loga
Substituting loga3=3loga in the equation f[g(a)]=loga3, we get
⇒f[g(a)]=3loga………(1)
Now, we will find the value of f[g(b)].
Substituting x=g(b) in the function f(x)=logx, we get
⇒f[g(b)]=log[g(b)]
Substituting g(b)=b3in the expression, we get
⇒f[g(b)]=logb3
Substituting x=b and n=3 in the rule of logarithms logxn=nlogx, we get
⇒logb3=3logb
Substituting logb3=3logb in the equation f[g(b)]=logb3, we get
⇒f[g(b)]=3logb………(2)
Finally, we will add equation (1) and equation (2) to get the value of the expression.
Adding equation (1) and equation (2), we get
⇒f[g(a)]+f[g(b)]=3loga+3logb
Factoring out 3 from the terms of the expression, we get
⇒f[g(a)]+f[g(b)]=3(loga+logb)
Now, we know the rule of logarithms logx+logy=log(xy). Here, the base of the terms must be equal.
Therefore, substituting x=a and y=b in the formula, we get
⇒loga+logb=log(ab)
Substituting loga+logb=log(ab) in the equation f[g(a)]+f[g(b)]=3(loga+logb), we get
⇒f[g(a)]+f[g(b)]=3log(ab)
Now, we can observe that since f(x)=logx, therefore f(ab)=log(ab).
Substituting log(ab)=f(ab) in the equation, we get
f[g(a)]+f[g(b)]=3f(ab)
Therefore, the value of the expression f[g(a)]+f[g(b)] is 3f(ab).
Thus, the correct option is option (b).
Note:
We can also solve this problem by simplifying the given options and comparing them to the simplified value f[g(a)]+f[g(b)]=3loga+3logb. However, we need to remember the rules of logarithms. A common mistake we can make while simplifying the options is to use logx+logy=log(x+y) which is not correct.