Question
Question: If e<sup></sup><sub>1</sub> and e<sub>2</sub> are the eccentricities of the conic sections 16x<sup>...
If e1 and e2 are the eccentricities of the conic sections 16x2 + 9y2 = 144 and 9x2 – 16y2 = 144, then-
A
e12+e22=3
B
e12+e22>3
C
e12+e22<3
D
e12−e22>1
Answer
e12+e22<3
Explanation
Solution
16x2 + 9y2 = 144 9x2 – 16y2 = 144
9x2 + 16y2 = 1 16x2 – 9y2 = 1
e1 = 1−169 e2 = 1+169
e1 = 47 e2 = 45
e12 + e22 = 167 + 1625 = 1632 = 2