Question
Question: If error in radius is 3 percent, then what is the error in volume of sphere in percentage? (A) 3 ...
If error in radius is 3 percent, then what is the error in volume of sphere in percentage?
(A) 3
(B) 27
(C) 9
(D) 6
Solution
Hint : In this question we need to find out the error in volume of sphere which means vΔv×100=?
And the error in radius is already given to us, that is rΔr×100=3% . Here we will use the formulae of volume of sphere to solve this question and we know that volume of sphere = 34πr3 , from this formula we can clearly observe that v is directly proportional to r.
volume of sphere = 34πr3 and percentage error δ=νE(νA−νE)⋅100%
Complete Step By Step Answer:
It is given that rΔr×100=3% where r is the radius (1)
We have to find percentage error in volume that is vΔv×100=? where v is the volume (2)
We know that volume of the sphere is 34πr3 which implies v≺r3 (v is directly proportional to r)
⇒ vΔv×100=3(rΔr)×100%
Therefore, by using equation (1) and (2) we have the equation
vΔv×100=3(rΔr)×100% = 3×3%=9%
Hence, the error in volume of the sphere will be 9% .
Note :
In the solution the terms like Δv and Δr are used which simply means change in velocity and change in radius. The formula for percentage error is δ=νE(νA−νE)⋅100% where, δ is assumed to be percentage error, νA is assumed to be actual value observed and νE is assumed to be expected value.
Here, we have to subtract the actual value and expected value and then divide the error by the exact value which you will get in decimal form, and hence to convert it into percentage we multiply the decimal number by 100.