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Question: If enthalpy of an overall reaction \(X \rightarrow Y\)along one route is \(\Delta_{r}H\) and \(\Delt...

If enthalpy of an overall reaction XYX \rightarrow Yalong one route is ΔrH\Delta_{r}H and ΔrH1ΔrH2ΔrH3....\Delta_{r}H_{1}\Delta_{r}H_{2}\Delta_{r}H_{3}.... representing enthalpies of reactions leading to same product Y then ΔrH\Delta_{r}H is

A

ΔrH=ΔrH1+ΔrH2+ΔrH3....\Delta_{r}H = \Delta_{r}H_{1} + \Delta_{r}H_{2} + \Delta_{r}H_{3}....

B

ΔrH=ΔrH1×ΔrH2×ΔrH3....\Delta_{r}H = \Delta_{r}H_{1} \times \Delta_{r}H_{2} \times \Delta_{r}H_{3}....

C

ΔrH=ΔrH1+ΔrH2ΔrH3....\Delta_{r}H = \Delta_{r}H_{1} + \Delta_{r}H_{2} - \Delta_{r}H_{3}....

D

ΔrH=ΔrH×ΔrH2×ΔrH32....\Delta_{r}H = \frac{\Delta_{r}H \times \Delta_{r}H_{2} \times \Delta_{r}H_{3}}{2}....

Answer

ΔrH=ΔrH1+ΔrH2+ΔrH3....\Delta_{r}H = \Delta_{r}H_{1} + \Delta_{r}H_{2} + \Delta_{r}H_{3}....

Explanation

Solution

: According to Hess’s law,

ΔrH=ΔrH1+ΔrH2+ΔrH3...\Delta_{r}H = \Delta_{r}H_{1} + \Delta_{r}H_{2} + \Delta_{r}H_{3}...

Where H1,H2,H3,H_{1},H_{2},H_{3}, etc. are enthalpies of various steps.