Question

If eleven members of a committee sit at a round table so that the President and Secretary always sit together, then the number of arrangements is.

• A. $10\mspace{6mu}!\mspace{6mu} \times 2$
• B. $10!$
• C. $9!\mspace{6mu} \times 2$
• D. None of these

Answer 1

Answer: (C)

$9!\mspace{6mu} \times 2$

Answer 2

Required number of ways $9\mspace{6mu}!\mspace{6mu} \times 2$.

{By fundamental property of circular permutation}.