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Question

Question: If electron falls from \(n = 3\) to \(n = 2\), then emitted energy is...

If electron falls from n=3n = 3 to n=2n = 2, then emitted energy is

A

10.2eV10.2eV

B

12.09eV12.09eV

C

1.9eV1.9eV

D

0.65eV0.65eV

Answer

1.9eV1.9eV

Explanation

Solution

ΔE=E3E2=13.6[1(2)21(3)2]=1.9eV\Delta E = E_{3} - E_{2} = 13.6\left\lbrack \frac{1}{(2)^{2}} - \frac{1}{(3)^{2}} \right\rbrack = 1.9eV