Question
Question: If electron falls from \(n = 3\) to \(n = 2\), then emitted energy is...
If electron falls from n=3 to n=2, then emitted energy is
A
10.2eV
B
12.09eV
C
1.9eV
D
0.65eV
Answer
1.9eV
Explanation
Solution
ΔE=E3−E2=13.6[(2)21−(3)21]=1.9eV