Question

If $E°(Zn^{2+},Zn)=-0.763\ V$ and $E°(Fe^{2+},Fe)=-0.44\ V$, then the emf of the cell $Zn/Zn^{2+}(a=0.001)||Fe^{2+}(a=0.005) Fe$ is

• A. equal to 0.323 V
• B. less than 0.323 V
• C. greater than 0.323 V
• D. equal to 1.103 V

Answer 1

Answer: (C)

greater than 0.323 V

Answer 2

The correct option is (C): greater than 0.323 V.