If (E°(Zn^{2+},Zn)=-0.763\ V) and (E°(Fe^{2+},Fe)=-0.44\ V),... | Chemistry | SolveeIt | Solveeit

Today, August 5

Question

If $E°(Zn^{2+},Zn)=-0.763\ V$ and $E°(Fe^{2+},Fe)=-0.44\ V$ , then the emf of the cell $Zn/Zn^{2+}(a=0.001)||Fe^{2+}(a=0.005) Fe$ is

A

equal to 0.323 V

B

less than 0.323 V

C

greater than 0.323 V

D

equal to 1.103 V

Answer

greater than 0.323 V

Explanation

Solution

The correct option is (C): greater than 0.323 V.