Question
Chemistry Question on EMF
If E°(Zn2+,Zn)=−0.763 V and E°(Fe2+,Fe)=−0.44 V, then the emf of the cell Zn/Zn2+(a=0.001)∣∣Fe2+(a=0.005)Fe is
A
equal to 0.323 V
B
less than 0.323 V
C
greater than 0.323 V
D
equal to 1.103 V
Answer
greater than 0.323 V
Explanation
Solution
The correct option is (C): greater than 0.323 V.