Solveeit Logo

Question

Question: If e1 is the eccentricity of the conic 9x2 + 4y2 = 36 and e2 is the eccentricity of the conic 9x2 – ...

If e1 is the eccentricity of the conic 9x2 + 4y2 = 36 and e2 is the eccentricity of the conic 9x2 – 4y2 = 36, then-

A

e12 + e22 = 2

B

e12 + e22> 3

C

e12 + e22< 2

D

e12 + e22> 4

Answer

e12 + e22> 3

Explanation

Solution

The equations in the standard form are x24+y29=1\frac{x^{2}}{4} + \frac{y^{2}}{9} = 1 and x24y29=1\frac{x^{2}}{4}–\frac{y^{2}}{9} = 1

e12=949=59,e22=4+94=134e_{1}^{2} = \frac{9–4}{9} = \frac{5}{9},e_{2}^{2} = \frac{4 + 9}{4} = \frac{13}{4} and e12e_{1}^{2}+ e22e_{2}^{2}

= 13736\frac{137}{36} > 3 but < 4.