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Question: If \(E\) is the electric field intensity of an electrostatic field, then the electrostatic energy de...

If EE is the electric field intensity of an electrostatic field, then the electrostatic energy density is proportional to

A

EE

B

E2E^{2}

C

1/E21/E^{2}

D

E3E^{3}

Answer

E2E^{2}

Explanation

Solution

Electrostatic energy density dUdV=12Kε0E2\frac{dU}{dV} = \frac{1}{2}K\varepsilon_{0}E^{2}∴ dUdV∝E2\frac{dU}{dV} \propto E^{2}