Question

If $E = at + bt^{2},$ what is the temperature of inversion

• A. $- \frac{a}{2b}$
• B. $+ \frac{a}{2b}$
• C. $- \frac{a}{b}$
• D. $+ \frac{a}{b}$

Answer 1

Answer: (A)

$- \frac{a}{2b}$

Answer 2

$E = at + bt^{2}$at inversion temperature E will be minimum. Thus $\frac{dE}{dt} = 0$ ⇒ $\frac{d}{dt}\lbrack at + bt^{2}\rbrack = 0$

⇒ $a + 2bt = 0$ ⇒ $t = - \frac{a}{2b}$