Question

If $E=at+bt^2,$ what is the neutral temperature?

• A. $-\frac {a}{2b}$
• B. $\frac {a}{2b}$
• C. $-\frac {a}{b}$
• D. $\frac {a}{b}$

Answer 1

Answer: (C)

$-\frac {a}{b}$

Answer 2

At temperature of inversion E is minimum, ie, E = 0 \hspace15mm E=at+bt^2 \therefore \hspace15mm 0=at_i+bt_i^2 or \hspace15mm t_i=- \frac {a}{b}