Question

If e and e' are the eccentricities of the ellipse 5x² + 9y² = 45 and the hyperbola 5x² – 4y² = 45 respectively, then ee' =

• A. 9
• B. 4
• C. 5
• D. 1

Answer 1

Answer: (D)

1

Answer 2

Clearly e = $\frac{2}{3}$and e' = $\frac{3}{2}$, ∴ ee' = 1