Question

If $\displaystyle\lim _{n \rightarrow \infty}\left(\sqrt{n^2-n-1}+n \alpha+\beta\right)=0$ then $8(\alpha+\beta)$ is equal to :

• A. 4
• B. $-8$
• C. -4
• D. 8

Answer 1

Answer: (C)

-4

Answer 2

The correct Option is(C): -4.