test","extracted_subject":"CHEMISTRY","extracted_chapter":"THERMODYNAMICS & THERMOCHEMISTRY","extracted_topic":"GIBBS ENERGY CHANGE AND EQUILIBRIUM","questionPreviewUrl":"https://cdn.pureessence.tech/question-previews/packed_canvases/canvas_1131.png?top_left_x=1064&top_left_y=1236&width=532&height=277&app=solveeit"},"seo_metadata":{"keywords":[]},"doubt_solver_data":{"concept_summary":[]},"embeddings":[],"is_hidden":false,"_id":"66d23e69425d76b7ab317529","slug":"if-dhsublatticesub-and-dhsubhydrationsub-of-nacl-a","content":"If DH_lattice and DH_hydration of NaCl are respectively 778 and –774.3 kJ mol^–1 and DS_dissolution of NaCl at 298 K is 43 J mol^–1. The value of DG° for dissolution of 1 mole of NaCl is –","options":[{"_id":"68dfdff28c3e555ae9e866a1","text":"–9.114 kJ","sequence":0,"isCorrect":true},{"_id":"68dfdff28c3e555ae9e866a2","text":"–11.14 kJ","sequence":1,"isCorrect":false},{"_id":"68dfdff28c3e555ae9e866a3","text":"–7.114 kJ","sequence":2,"isCorrect":false},{"_id":"68dfdff28c3e555ae9e866a4","text":"+ 9.114 kJ","sequence":3,"isCorrect":false}],"correct_answer":"–9.114 kJ","explanation":"DH_diss. = DH_L + DH_Hyd.\n\n= 778 + (–774. 3) = 3.7 kJ\n\nDG_diss. = DH_diss. – T DS_diss","question_type":"single_choice","appeared_in":[],"created_at":"2024-08-30T21:49:29.471Z","__v":0,"vector_store_id":"8db2fb30-7032-4a7e-bf78-23580ae4b498","updated_at":"2024-08-30T21:49:29.471Z","isStarred":false},"params":{"questionSlug":"if-dhsublatticesub-and-dhsubhydrationsub-of-nacl-a"}}]}]]

Question: If DH<sub>lattice</sub> and DH<sub>hydration</sub> of NaCl are respectively 778 and –774.3 kJ mol<su...

Solution