Question
Question: If \( \dfrac{{\log 64}}{{\log 8}} = \log x, \) then value of x is A. \( 100 \) B. \( 112 \) ...
If log8log64=logx, then value of x is
A. 100
B. 112
C. 165
D. 95
Solution
Hint : Logarithms are ways to figure out which exponents we need to multiply into the specific number. Here, using the property of logarithm the change of base, According to the power rule, the log of a power is equal to the power times the log of the base.
logbaN=Nlogba
Complete step-by-step answer :
Take the given expression –
log8log64=logx
Now, the number can be written as the square of number. 64=82
⇒log8log82=logx
By using the power rule - the log of a power is equal to the power times the log of the base.
logbaN=Nlogba
⇒log82log8=logx
Common multiples from the numerator and denominator cancel each other.
⇒2=logx
Let us assume the base 10 of the logarithm.
Simplify the above equation –
⇒x=102
Simplify the above equation by placing the square of the number. As we know that 102=100
⇒x=100
Hence from the given multiple choices – the option A is the correct answer.
So, the correct answer is “Option A”.
Note : In other words, the logarithm is the power to which the number must be raised in order to get some other. Always remember the standard properties of the logarithm.... Product rule, quotient rule and the power rule. The basic logarithm properties are most important and the solution solely depends on it, so remember and understand its application properly. Be good in multiples and know the concepts of square and square root and apply accordingly.
Also refer to the below properties and rules of the logarithm.
Product rule: logaxy=logax+logay
Quotient rule: logayx=logax−logay
Power rule: logaxn=nlogax
Base rule: logaa=1
Change of base rule: logaM=logNlogM