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Question

Physics Question on Gravitation

If density of earth increases 44 times and its radius becomes half of what it is, our weight will

A

be 4 times its present value

B

be doubled

C

remain same

D

be halved

Answer

be doubled

Explanation

Solution

Weight, w=mg=m43πGRρw = mg = m \frac{4}{3} \pi GR \rho Now that: R=R/2R'=R / 2 and ρ=4ρ\rho'=4 \rho ww=RρRρ=(12)×4=2\therefore \frac{w'}{w}=\frac{R' \rho'}{R \rho}=\left(\frac{1}{2}\right) \times 4=2 w=2ww'=2 w Hence our weight will be doubled.