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Question: If \(\Delta = \left| \begin{matrix} x & y & z \\ p & q & r \\ a & b & c \end{matrix} \right|,\) then...

If Δ=xyzpqrabc,\Delta = \left| \begin{matrix} x & y & z \\ p & q & r \\ a & b & c \end{matrix} \right|, then x2yz2p4q2ra2bc\left| \begin{matrix} x & 2y & z \\ 2p & 4q & 2r \\ a & 2b & c \end{matrix} \right|equals.

A

Δ2\Delta^{2}

B

4Δ4\Delta

C

3Δ3\Delta

D

None of these

Answer

4Δ4\Delta

Explanation

Solution

Let Δ1=x2yz2p4q2ra2bc\Delta_{1} = \left| \begin{matrix} x & 2y & z \\ 2p & 4q & 2r \\ a & 2b & c \end{matrix} \right|=4xyzpqrabc=4Δ4\left| \begin{matrix} x & y & z \\ p & q & r \\ a & b & c \end{matrix} \right| = 4\Delta.

(Taking common '2' from IInd row and '2' from IInd column).