Question: If $\Delta G_{T} = nRT\ln\frac{V_{2}}{V_{1}}$ $\Delta G_{T} = nRT\log\frac{P_{1}}{P_{2}}$ \[\De...

Question

If $\Delta G_{T} = nRT\ln\frac{V_{2}}{V_{1}}$ $\Delta G_{T} = nRT\log\frac{P_{1}}{P_{2}}$

$\Delta G_{T} = nRT\log\frac{V_{2}}{V_{1}}$

then the possible heat of methane will be.

Answer 1

$1atm$ …..(i)

$100^{o}C$ ….(ii)

On multiplication of eq. (ii) by 2 and than adding in

eq. (i)

$1atm$ …(iii)

On subtracting eq. (iii) by following eq.

$\Delta G$ we get,

$540cal$

Question: If \(\Delta G_{T} = nRT\ln\frac{V_{2}}{V_{1}}\) \(\Delta G_{T} = nRT\log\frac{P_{1}}{P_{2}}\) \[\De...