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Question

Mathematics Question on Matrices

If Δ1=xbb\axb\aax\Delta_1=\begin{vmatrix} x&b&b \\\a&x&b\\\a&a&x\end{vmatrix} and Δ2=xb\ax\Delta_2=\begin{vmatrix} x&b \\\a&x\end{vmatrix}, then ddx(Δ1)\frac{d}{dx}(\Delta_1) is equal to

A

3(Δ2)23(\Delta_2)^2

B

3(Δ2)123(\Delta_2)^{\frac{1}{2}}

C

3Δ23\Delta_2

D

3Δ223\Delta_2^2

Answer

3Δ23\Delta_2

Explanation

Solution

The correct option is (C): 3Δ23\Delta_2