Question

If D = $\left| \begin{matrix} 1 & 2 & 3 \\ 2 & - 1 & 0 \\ 3 & 4 & 5 \end{matrix} \right|$, then $\left| \begin{matrix} 1 & 6 & 3 \\ 4 & - 6 & 0 \\ 3 & 12 & 5 \end{matrix} \right|$ is

• A. 2D
• B. 3D
• C. 6D
• D. 0

Answer 1

Answer: (C)

6D

Answer 2

$\left| \begin{matrix} 1 & 6 & 3 \\ 4 & - 6 & 0 \\ 3 & 12 & 5 \end{matrix} \right|$=3$\left| \begin{matrix} 1 & 2 & 3 \\ 4 & - 2 & 0 \\ 3 & 4 & 5 \end{matrix} \right|$= 3.2$\left| \begin{matrix} 1 & 2 & 3 \\ 2 & - 1 & 0 \\ 3 & 4 & 5 \end{matrix} \right|$= 6 D