Question
Question: If \(\cos\theta + \cos 2\theta + \cos 3\theta = 0,\) then the general value of \(\theta\)is...
If cosθ+cos2θ+cos3θ=0, then the general value of θis
A
θ=2mπ±32π
B
θ=2mπ±4π
C
θ=mπ+(−1)m32π
D
θ=mπ+(−1)m3π
Answer
θ=2mπ±32π
Explanation
Solution
⇒cosθ+cos2θ+cos3θ=0⇒(cosθ+cos3θ)+cos2θ=0⇒2cos2θ.cosθ+cos2θ=0⇒cos2θ(2cosθ+1)=0
⇒cos2θ=0=cos2π⇒ 2θ=2mπ±π/2 ⇒θ=mπ±4π or
cosθ=−21=cos32π ⇒θ=2mπ±32π.