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Question

Mathematics Question on Trigonometry

If cos2θ+sinθ=2cosθ,Then cosθsinθ=?cos2\theta+sin\theta= \sqrt{2}cos \theta,Then \ cos\theta-sin \theta=?

A

2cosθ\sqrt{2}cos\theta

B

2sinθ2sin\theta

C

2sinθ\sqrt2sin\theta

D

2cosθ2cos\theta

Answer

2sinθ\sqrt2sin\theta

Explanation

Solution

The correct option is (C):2sinθ\sqrt2sin\theta