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Question: If \(\cos ec_{}^2\theta + \cot _{}^2\theta = 7\), what is the value of (in degrees) of \(\theta \)? ...

If cosec2θ+cot2θ=7\cos ec_{}^2\theta + \cot _{}^2\theta = 7, what is the value of (in degrees) of θ\theta ?
(1) 15\left( {\text{1}} \right){\text{ 15}}
(2) 30\left( 2 \right){\text{ 30}}
(3) 45\left( 3 \right){\text{ 45}}
(4) 60\left( 4 \right){\text{ 60}}

Explanation

Solution

This question can be easily solved by using the formula of from which we get, cosec2θ=1+cot2θ\cos ec_{}^2\theta = 1 + \cot _{}^2\theta by moving cot2θ\cot _{}^2\theta to the right side. After getting the value of cosec2θ\cos ec_{}^2\theta we can substitute it in the given equation cosec2θ+cot2θ=7\cos ec_{}^2\theta + \cot _{}^2\theta = 7 and by doing this we will get the value of θ\theta .

Formula used: cosec2θcot2θ=1\cos ec_{}^2\theta - \cot _{}^2\theta = 1
cot300=3\cot 30_{}^0 = \sqrt 3

Complete step-by-step answer:
It is given that cosec2θ+cot2θ=7....(1)\cos ec_{}^2\theta + \cot _{}^2\theta = 7....\left( 1 \right)
Since we know that cosec2θcot2θ=1\cos ec_{}^2\theta - \cot _{}^2\theta = 1
From this formula, we can write the value of cosec2θ\cos ec_{}^2\theta by moving cot2θ\cot _{}^2\theta to the right hand side
cosec2θ=1+cot2θ\cos ec_{}^2\theta = 1 + \cot _{}^2\theta
Now by putting the value of cosec2θ=1+cot2θ\cos ec_{}^2\theta = 1 + \cot _{}^2\theta in equation (1)\left( 1 \right)
1+cot2θ1 + \cot _{}^2\theta + cot2θ=7\cot _{}^2\theta = 7
On adding the terms we get-
1+2cot2θ=71 + 2\cot _{}^2\theta = 7
Now by moving the term 11 on the right hand side we get-
2cot2θ=712\cot _{}^2\theta = 7 - 1
After doing subtraction we get-
2cot2θ=62\cot _{}^2\theta = 6
Now for getting the value of cot2θ\cot _{}^2\theta so we have to divide 66 by 22 and we get
cot2θ=3\cot _{}^2\theta = 3
In order to get the value of cotθ\cot \theta , taking square on both side
cotθ=3\cot \theta = \sqrt 3
Since the value of cot300=3\cot 30_{}^0 = \sqrt 3 so we can write
cotθ=cot300\cot \theta = \cot 30_{}^0
Therefore by applying cancellation technique we get
θ=300\theta = 30_{}^0
Thus the value of cosec2θ+cot2θ=7\cos ec_{}^2\theta + \cot _{}^2\theta = 7 is 30030_{}^0

So, the correct answer is “Option 2”.

Note: There are two ways of solving this question, one is by applying a substitution method and other is elimination method.
In both the cases we have to apply the formula of cosec2θcot2θ=1\cos ec_{}^2\theta - \cot _{}^2\theta = 1.
In case of substitution method you need substitute the value of cosec2θ\cos ec_{}^2\theta in the given equation and can find out the value of θ\theta
But in the elimination method you need to eliminate one and find the value of the other and at last after getting the value of one you will be able to get the value of θ\theta .