QuestionReportMathematics Question on Trigonometric EquationsIf Cos−1p+Cos−1q+Cos−1r=πCos^{-1} p + Cos ^{-1} q + Cos ^{-1} r = \pi Cos−1p+Cos−1q+Cos−1r=π then p2+q2+r2+2pqr=p^{2} + q^{2} +r^{2} +2pqr=p2+q2+r2+2pqr=A3B1C2D−1-1−1Answer1ExplanationSolutionAnswer (b) 1