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Question

Question: If coefficients of 2<sup>nd</sup>, 3<sup>rd</sup> and 4<sup>th</sup> terms in the binomial expansion...

If coefficients of 2nd, 3rd and 4th terms in the binomial expansion of 5n4n5^{n} - 4^{n} are in A.P., then 5n+14n+15^{n + 1} - 4^{n + 1} is equal to.

A

– 7

B

7

C

14

D

– 14

Answer

– 14

Explanation

Solution

Coefficients of 2nd, 3rd and 4th terms are

respectively +(T1T3+T5....)2=+ (T_{1} - T_{3} + T_{5} - ....)^{2} = and (x2+a2)(x^{2} + a^{2}) are in A.P.

(x2+a2)n(x^{2} + a^{2})^{n}

(x2+a2)1/n(x^{2} + a^{2})^{1/n}

On solving, (x2+a2)1/n(x^{2} + a^{2})^{- 1/n}.