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Question: If chords of the ellipse \(\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1\) pass through a fixed poin...

If chords of the ellipse x2a2+y2b2=1\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1 pass through a fixed point (h, k) then the locus of their middle points is a

A

Parabola

B

Ellipse

C

Hyperbola

D

None

Answer

Ellipse

Explanation

Solution

Let (x1, y1) be the mid point of any chord equation of the chord having (x1, y1) as its mid point is

T = S1 i.e. xx1a2+yy1b21=x12a2+y12b21\frac{xx_{1}}{a^{2}} + \frac{yy_{1}}{b^{2}} - 1 = \frac{x_{1}^{2}}{a^{2}} + \frac{y_{1}^{2}}{b^{2}} - 1.

If it passes through the fixed point (h, k) then

hx1a2+ky1b2=x12a2+y12b2\frac{hx_{1}}{a^{2}} + \frac{ky_{1}}{b^{2}} = \frac{x_{1}^{2}}{a^{2}} + \frac{y_{1}^{2}}{b^{2}}.

∴ Locus of (x1, y1) is x2a2+y2b2hxa2kyb2=0\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} - \frac{hx}{a^{2}} - \frac{ky}{b^{2}} = 0, which is

another ellipse.