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Question

Chemistry Question on Solutions

If χ1\chi_{1} and χ2\chi_{2} represent the mole fractions of a component AA in the vapour phase and liquid mixture respectively, and pAp^{\circ}_{A} and pBp^{\circ}_{B} represent vapour pres sines of pure A and pure B, then total vapour pressure of liquid mixture is

A

ρAχ1χ2\frac{\rho^{\circ}_{A}\chi_{1}}{\chi_{2}}

B

ρAχ2χ1\frac{\rho^{\circ}_{A}\chi_{2}}{\chi_{1}}

C

ρBχ1χ2\frac{\rho^{\circ}_{B}\chi_{1}}{\chi_{2}}

D

ρBχ2χ1\frac{\rho^{\circ}_{B}\chi_{2}}{\chi_{1}}

Answer

ρAχ2χ1\frac{\rho^{\circ}_{A}\chi_{2}}{\chi_{1}}

Explanation

Solution

Mole fraction in the vapour phase (χ1)=pAptotal\left(\chi_{1}\right)=\frac{p_{A}}{p_{total}}
But, PA×χA×pA=χ2pAP_{A}\times\chi_{A}\times p_{A}^{\circ}=\chi_{2}p_{A}^{\circ}
or χ1×pA(asχA=χ1) \chi_{1}\times p_{A}^{\circ} \left(as \chi_{A}=\chi_{1}\right)
χ1=χ2pAptotal\therefore \chi_{1}=\frac{\chi_{2}p_{A}^{\circ}}{p_{total}}
or ptotal=pAχ2χ1p_{total}=\frac{p^{\circ}_{A}\chi_{2}}{\chi_{1}}