Question

If charge and distance between two charges are reduced to half. Force between them

• A. remains same
• B. increases four times
• C. reduce four times
• D. None of the above

Answer 1

Answer: (A)

remains same

Answer 2

As per Coulomb's law $F = k \frac{q_{1} q_{2}}{r^{2}}$
According to question,
$F'= k \frac{\left(q_{1} / 2\right)\left(q_{2} / 2\right)}{(r / 2)^{2}}$
$=k \frac{q_{1} q_{2}}{r^{2}}=F$
Thus, force between them will remain same.