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Question: If change in energy \((\Delta E) = 3 \times 10^{- 8}J,h = 6.64 \times 10^{- 34}J - s\) and \(c = 3 \...

If change in energy (ΔE)=3×10−8J,h=6.64×10−34J−s(\Delta E) = 3 \times 10^{- 8}J,h = 6.64 \times 10^{- 34}J - s and c=3×108m⥂/⥂s,c = 3 \times 10^{8}m ⥂ / ⥂ s, then wavelength of the light is

A

6.36×103A˚6.36 \times 10^{3}Å

B

6.36×105A˚6.36 \times 10^{5}Å

C

6.64×10−8A˚6.64 \times 10^{- 8}Å

D

6.36×1018A˚6.36 \times 10^{18}Å

Answer

6.64×10−8A˚6.64 \times 10^{- 8}Å

Explanation

Solution

ΔE=hcλ\Delta E = \frac{hc}{\lambda} or λ=hcΔE\lambda = \frac{hc}{\Delta E}

=6.64×10−34×3×1083×10−8=6.64×10−8A˚= \frac{6.64 \times 10^{- 34} \times 3 \times 10^{8}}{3 \times 10^{- 8}} = 6.64 \times 10^{- 8}Å