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Question: If CH3COOH + OH–\(\rightarrow\)CH3COO– + H2O + q1 H+ + OH–\(\rightarrow\)H2O + q2 then the enthalp...

If CH3COOH + OH–→\rightarrowCH3COO– + H2O + q1

H+ + OH–→\rightarrowH2O + q2

then the enthalpy change for the reaction

CH3COOH →\rightarrow CH3COO– + H+ is equal to

A

(q1 + q2)

B

(q1 – q2)

C

(q2 – q1)

D

– (q1 + q2)

Answer

(q2 – q1)

Explanation

Solution

Eqn. (ii) is for heat of neutralisation of strong acid with strong base. Eqn. (i) for weak acid with strong base. The difference q2 – q1 is heat of dissociation of weak acid.