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Question

Question: If \(C_{V} = 4.96cal/mole\) K, then increase in internal energy when temperature of 2 moles of this ...

If CV=4.96cal/moleC_{V} = 4.96cal/mole K, then increase in internal energy when temperature of 2 moles of this gas is increased from 340 K to 342 K

A

27.80 cal

B

19.84 cal

C

13.90 cal

D

9.92 cal

Answer

19.84 cal

Explanation

Solution

ΔU=μCVΔT=2×4.96×(342340)=19.846mucal\Delta U = \mu C_{V}\Delta T = 2 \times 4.96 \times (342 - 340) = 19.84\mspace{6mu} cal