Question
Mathematics Question on Binomial theorem
If C0,C1,C2,…,Cn denote the coefficients in the expansion of (1+x)n, then the value of C1+2C2+3C3+…+nCn is
A
n⋅2n−1
B
(n+1)2n−1
C
(n+1)2n
D
(n+2)2n−1
Answer
n⋅2n−1
Explanation
Solution
Since,
If C0,C1,C2,…,Cn denote the coefficients in the expansion of (1+x)n, then the value of C1+2C2+3C3+…+nCn is
n⋅2n−1
(n+1)2n−1
(n+1)2n
(n+2)2n−1
n⋅2n−1
Since,