Question
Question: If c \> 0 and 4a + c \< 2b then ax<sup>2</sup> – bx + c = 0 has a root in the interval...
If c > 0 and 4a + c < 2b then ax2 – bx + c = 0 has a root in the interval
A
(0, 2)
B
(2, 4)
C
(0, 1)
D
(–2, 0)
Answer
(0, 2)
Explanation
Solution
Let f(x) = ax2 – bx + c
f(0) = c > 0 and f(2) = 4a –2b + c < 0 so that f(x) = 0 has a root in the interval (0, 2)