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Question

Physics Question on Gravitation

If both the mass and radius of earth decrease by 1%1\%, the value of (I) acceleration due to gravity would increase by 1%1\% (II) acceleration due to gravity would decrease by 1%1\% (III) escape velocity from earth's surface would decrease by 1%1 \% (IV) the gravitational potential energy of a body on earth's surface will remain unchanged

A

(I) and (III)

B

(I) and (IV)

C

(II) and (IV)

D

(III) and (IV)

Answer

(II) and (IV)

Explanation

Solution

If both the mass and radius of the earth decrease by 1%1 \%, the value of acceleration due to gravity g=g(0.99Me)(0.99Re)21.01GMeRe2=1.01gg'=\frac{g\left(0.99 M_{e}\right)}{\left(0.99 R_{e}\right)^{2}} \approx 1.01 \frac{G M_{e}}{R_{e}^{2}}=1.01 g So, gg would increase by (1.011)×100%=1%(1.01-1) \times 100 \%=1 \% New escape velocity would be ve=2×0.99MGe0.99Rev_{e}'=\sqrt{\frac{2 \times 0.99 M- G_e}{0.99 R_{e}}} =2GMeRe=ve=\sqrt{\frac{2 G M_{e}}{R_{e}}}=v_{e} So, it will remain unchanged. Also gravitational potential energy =Gm(0.99me)0.99Re=\frac{G m\left(0.99 m_{e}\right)}{0.99 R_{e}} =GMemRe=-\frac{G M_{e} m}{R_{e}} Hence, it also will remain same.