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Question

Physics Question on thermal properties of matter

If boiling point of water is 95F,95{}^\circ F, what will be reduction at celsius scale?

A

7C7{}^\circ C

B

65C65{}^\circ C

C

63 C63{}^\circ \text{ }C

D

35C35{}^\circ C

Answer

35C35{}^\circ C

Explanation

Solution

The relation between Celsius scale and Fahrenheit scale is as derived below:

100100 parts of Celsius scale =180= 180 parts of Fahrenheit scale
\therefore 1 part of Celsius scale
=95=\frac{9}{5} parts of Fahrenheit scale Hence, TF=32+95TC{{T}_{F}}=32+\frac{9}{5}{{T}_{C}} Or TC=59(TF32){{T}_{C}}=\frac{5}{9}({{T}_{F}}-32)
Given, TF=95oF{{T}_{F}}={{95}^{o}}F
\therefore TC=59(9532){{T}_{C}}=\frac{5}{9}(95-32)
=35oC={{35}^{o}}C