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Question

Mathematics Question on Determinants

If a5xp b10y5 c15z15=125\begin{vmatrix}a&5x&p\\\ b&10y&5\\\ c&15z&15\end{vmatrix} = 125, then find the value of 3a3bc x2yz p55\begin{vmatrix}3a&3b&c\\\ x&2y&z\\\ p&5&5\end{vmatrix}

A

25

B

125

C

5

D

10

Answer

25

Explanation

Solution

3a3bc x2yz p55=3axp 3b2y5 cz5\begin{vmatrix}3a&3b&c\\\ x&2y&z\\\ p&5&5\end{vmatrix} = \begin{vmatrix}3a&x&p\\\ 3b&2y&5\\\ c&z&5\end{vmatrix} [changing rows intocolumns] =133axp 3b2y5 3c3z15=33×15a5xp b10y5 c15z15=15(125)=25= \frac{1}{3} \begin{vmatrix}3a&x&p\\\ 3b&2y&5\\\ 3c&3z&15\end{vmatrix} = \frac{3}{3}\times\frac{1}{5} \begin{vmatrix}a&5x&p\\\ b&10y&5\\\ c&15z&15\end{vmatrix} = \frac{1}{5}\left( 125\right) = 25