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Question

Mathematics Question on Determinant

If [x+42x2x\[0.3em]2xx+42x\[0.3em]2x2xx+4]=λ(4x)2\begin{bmatrix} x+4 & 2x & 2x \\\[0.3em] 2x & x+4 & 2x\\\[0.3em] 2x & 2x & x+4 \end{bmatrix}=\lambda(4-x)^2,then value of λ\lambda is

A

λ=4x+5\lambda=4x+5

B

λ=5x+4\lambda=5x+4

C

λ=4x\lambda=4-x

D

λ=x4\lambda=x-4

Answer

λ=5x+4\lambda=5x+4

Explanation

Solution

The correct option is (B): λ=5x+4\lambda=5x+4