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Question: If α, β be the roots of x<sup>2</sup> + px – q = 0 &γ, δ  be the roots of x<sup>2</sup> + px + r = ...

If α, β be the roots of x2 + px – q = 0 &γ, δ  be the roots of

x2 + px + r = 0 then (αγ)(αδ)(βγ)(βδ)\frac{(\alpha - \gamma)(\alpha - \delta)}{(\beta - \gamma)(\beta - \delta)} =

A

1

B

q

C

r

D

q + r

Answer

1

Explanation

Solution

α+β=pγ+δ=pα+β=γ+δ\begin{array} { l } \alpha + \beta = - p \\ \gamma + \delta = - p \end{array} \quad \Rightarrow \alpha + \beta = \gamma + \delta

Now, (α − γ) (α − δ) = α2 − α (γ + δ) + γδ

= α2 − α (α + β) + r

= −αβ + r = q + r

By symmetry of result,

(β – γ) (β – δ) = q + r

Hence ratio is 1