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Question: If \(\bar a,\bar b,\bar c\) are position vectors of vertices \(A,B,C\) of \(\Delta ABC\) . If \(\bar...

If aˉ,bˉ,cˉ\bar a,\bar b,\bar c are position vectors of vertices A,B,CA,B,C of ΔABC\Delta ABC . If rˉ\bar r is a position vector of a point PP such that (bˉcˉ+cˉaˉ+aˉbˉ)rˉ=bˉcˉaˉ+cˉaˉbˉ+aˉbˉcˉ\left( {\left| {\bar b - \bar c} \right| + \left| {\bar c - \bar a} \right| + \left| {\bar a - \bar b} \right|} \right)\bar r = \left| {\bar b - \bar c} \right|\bar a + \left| {\bar c - \bar a} \right|\bar b + \left| {\bar a - \bar b} \right|\bar c then the point PP is
A) Centroid of ΔABC\Delta ABC
B) Orthocentre of ΔABC\Delta ABC
C) Circumcentre of ΔABC\Delta ABC
D) Incentre of ΔABC\Delta ABC

Explanation

Solution

First we have given the position vectors of all the vertices so we will use the position vectors to determine the vector representation of each side. Now modulus of the vector will represent the length of the side. We will then rearrange the terms of the given equality and observe what it represents.

Complete step by step solution:
It is given that aˉ,bˉ,cˉ\bar a,\bar b,\bar c are position vectors of vertices A,B,CA, B, C of ΔABC\Delta ABC.
Also, it is given that rˉ\bar r represents the position vector of point PP.
Now, the modulus of the difference between the position vectors will represent the length of each side.
We will find the length of each side in terms of the position vector corresponding to the vertices.
First, we will consider the side ABAB.
The length of the side will be given by:
AB=bˉaˉAB = \left| {\bar b - \bar a} \right|
Similarly, now we will consider the side BCBC.
The length of the side will be given by:
BC=cˉbˉBC = \left| {\bar c - \bar b} \right|
Finally, we will consider the side CACA.
The length of the side will be given by:
CA=aˉcˉCA = \left| {\bar a - \bar c} \right|
Now we have determined all the lengths.
We will consider the given equation as follows:
(bˉcˉ+cˉaˉ+aˉbˉ)rˉ=bˉcˉaˉ+cˉaˉbˉ+aˉbˉcˉ\left( {\left| {\bar b - \bar c} \right| + \left| {\bar c - \bar a} \right| + \left| {\bar a - \bar b} \right|} \right)\bar r = \left| {\bar b - \bar c} \right|\bar a + \left| {\bar c - \bar a} \right|\bar b + \left| {\bar a - \bar b} \right|\bar c
Rearrange the given terms and express the above equation for the position vector rˉ\bar r .
rˉ=bˉcˉaˉ+cˉaˉbˉ+aˉbˉcˉ(bˉcˉ+cˉaˉ+aˉbˉ)\bar r = \dfrac{{\left| {\bar b - \bar c} \right|\bar a + \left| {\bar c - \bar a} \right|\bar b + \left| {\bar a - \bar b} \right|\bar c}}{{\left( {\left| {\bar b - \bar c} \right| + \left| {\bar c - \bar a} \right| + \left| {\bar a - \bar b} \right|} \right)}}
Now the denominator is the sum of lengths of the triangle that represents the parameter. Also, the numerator is of the form ax+by+czax + by + cz. Thus, the whole expression represents the incentre of the triangle.

Hence, the correct option is D.

Note:
Note that if you are not able to visualise the process then draw the diagram for better understanding. Also, it is important to observe the given equation and rearrange the terms accordingly. Finally interpret the obtained result to reach the final answer.