If (b^{2} + c^{2} = 0) | MATH - CONJUGATE, MODULUS AND ARGUMENT OF COMPLEX NUMBERS | SolveeIt

If $b^{2} + c^{2} = 0$

$a^{2} + c^{2} = 0$

$b^{2} + d^{2} = 0$

$z = x + iy,z^{1/3} = a - ib$

$\frac{x}{a} - \frac{y}{b} = k(a^{2} - b^{2})$

Answer

$z = x + iy,z^{1/3} = a - ib$

Explanation

$\frac{2 - 3i}{4 - i} = \frac{(2 - 3i)(4 + i)}{(4 + i)(4 - i)}$ , $= \frac{8 + 3 - 12i + 2i}{16 + 1}$

$= \frac{11 - 10i}{17} = \frac{11 + 10i}{17}$

$z = 1 + i$

Hence, $\bar{z} = 1 - i$ .

Question: If \(b^{2} + c^{2} = 0\)...