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Question

Quantitative Aptitude Question on Logarithms

If bx=ayb^x=a^y then,

A

logalogb=yx\frac{log a}{log b}=\frac{y}{x}

B

logbloga=yx\frac{log b}{log a}=\frac{y}{x}

C

logbloga=xy\frac{log b}{log a}=\frac{x}{y}

D

Can't be determined

Answer

logbloga=yx\frac{log b}{log a}=\frac{y}{x}

Explanation

Solution

The correct option is (B): logbloga=yx\frac{log b}{log a}=\frac{y}{x}